Module M09 Quiz: Serial Correlation
12 questions · Graduate (ECMT5001) · MCQ, calculation, short answer
How to use
Attempt each question before clicking Show Answer. Many serial correlation questions ask you to state H₀, compute a test statistic, and reach a conclusion.
Question 1
Lesson L01 · Definition
Serial correlation (autocorrelation) in time-series errors means:
Type: Multiple Choice
- A) \(\text{Var}(u_t \mid x_t) \neq \sigma^2\) (heteroskedasticity)
- B) \(\text{Cov}(u_t, u_{t-s}) \neq 0\) for some lag \(s \neq 0\)
- C) \(E(u_t \mid x_t) \neq 0\) (endogeneity)
- D) Errors are not normally distributed
Show Answer
Answer: B
Serial correlation means past errors predict current errors — shocks persist over time. The most common pattern is positive AR(1): \(u_t = \rho u_{t-1} + e_t\) with \(\rho > 0\). This means: - A positive shock this period → likely positive error next period - The error process has "memory"
Common causes: omitted slowly-changing variables (e.g. technology, preferences), misspecified dynamics (lagged effects of regressors not modelled), or sluggish adjustment in economic processes.
Question 2
Lesson L01 · Consequences
With AR(1) serial correlation \(u_t = \rho u_{t-1} + e_t\) (\(0 < \rho < 1\)), OLS is:
Type: Multiple Choice
- A) Biased and inconsistent — OLS cannot be used
- B) Unbiased and consistent (under strict exogeneity), but not BLUE; OLS standard errors are biased — typically understated with positive \(\rho\)
- C) Still BLUE — serial correlation only affects efficiency when \(\rho > 0.5\)
- D) Only a problem when \(\rho > 0.9\)
Show Answer
Answer: B
Under strict exogeneity (which holds for most static time-series models), OLS is unbiased — serial correlation in \(u\) doesn't mean \(E(u_t \mid x_t) \neq 0\).
However: Gauss-Markov requires \(\text{Var}(\mathbf{u}) = \sigma^2 I\) (spherical errors). With serial correlation, \(\text{Var}(\mathbf{u}) \neq \sigma^2 I\) → OLS is not BLUE (GLS is more efficient). The OLS variance formula \(\hat{\text{Var}}(\hat{\beta}) = \hat{\sigma}^2 (X'X)^{-1}\) is wrong — it typically understates the true variance with positive \(\rho\), making \(t\)-statistics too large and inference too liberal.
Question 3
Lesson L02 · Durbin-Watson
The Durbin-Watson statistic is \(DW \approx 2(1 - \hat{\rho})\) where \(\hat{\rho}\) is the first-order autocorrelation of residuals. If \(DW = 0.6\), what does this imply?
Type: Calculation
Show Answer
\(\hat{\rho} = 0.7\) indicates strong positive serial correlation — each error predicts 70% of the next error. \(DW = 0.6 \ll 2\) is well below the "no autocorrelation" value of 2.
DW ranges: - \(DW \approx 2\): no serial correlation (\(\hat{\rho} \approx 0\)) ✓ - \(DW \approx 0\): strong positive serial correlation (\(\hat{\rho} \approx 1\)) ✗ - \(DW \approx 4\): strong negative serial correlation (\(\hat{\rho} \approx -1\)) ✗
Question 4
Lesson L02 · DW Limitations
The Durbin-Watson test is invalid when:
Type: Multiple Choice
- A) The sample size exceeds 100
- B) A lagged dependent variable \(y_{t-1}\) appears as a regressor
- C) The regressors are trending
- D) The errors are heteroskedastic
Show Answer
Answer: B
The DW test assumes that regressors are strictly exogenous. When \(y_{t-1}\) is a regressor, it is correlated with \(u_{t-1}\) by construction (since \(y_{t-1}\) depends on \(u_{t-1}\)). This violates strict exogeneity and biases the DW test — it tends to be biased toward 2 (appearing to find no autocorrelation even when it exists).
Alternative: Use the Breusch-Godfrey (BG) LM test, which is valid with lagged dependent variables and can test for higher-order serial correlation (\(p\) lags).
Question 5
Lesson L02 · Breusch-Godfrey Test
[Short Answer] Describe the Breusch-Godfrey test procedure for AR(\(p\)) serial correlation.
Type: Short Answer
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Steps:
- Estimate the original regression by OLS; obtain residuals \(\hat{u}_t\)
- Regress \(\hat{u}_t\) on the original regressors \(\mathbf{x}_t\) and \(p\) lagged residuals \(\hat{u}_{t-1}, \hat{u}_{t-2}, \ldots, \hat{u}_{t-p}\)
- Compute LM statistic: \(LM = (n-p) \cdot R^2_{\text{aux}} \sim \chi^2_p\) under \(H_0\)
- Reject \(H_0\): \(\rho_1 = \rho_2 = \cdots = \rho_p = 0\) if \(LM > \chi^2_{p,\alpha}\)
Advantages over DW: - Valid when lagged \(y\) appears as a regressor - Tests for any order \(p\) of serial correlation - Based on standard asymptotic chi-squared distribution (no special tables needed)
Question 6
Lesson L02 · BG Test — Calculation
[Calculation] You run the BG test with \(p = 2\) lags. The auxiliary regression of \(\hat{u}_t\) on \(x_t\), \(\hat{u}_{t-1}\), \(\hat{u}_{t-2}\) gives \(R^2 = 0.12\) with \(n = 100\) observations. Test at the 5% level. \(\chi^2_{2, 0.05} = 5.99\).
Type: Calculation
Show Answer
Since \(LM = 11.76 > \chi^2_{2, 0.05} = 5.99\), reject \(H_0\) at the 5% level. There is significant evidence of serial correlation up to order 2. OLS standard errors are unreliable — use Newey-West (HAC) standard errors or GLS.
Question 7
Lesson L03 · Newey-West Standard Errors
Newey-West (HAC) standard errors are valid in the presence of serial correlation. They:
Type: Multiple Choice
- A) Change the OLS coefficient estimates to remove the serial correlation bias
- B) Correct the reported standard errors to be valid asymptotically under serial correlation (and heteroskedasticity), without changing \(\hat{\beta}\)
- C) Are only valid for AR(1) processes
- D) Require knowing the order of serial correlation
Show Answer
Answer: B
Newey-West SEs use a heteroskedasticity and autocorrelation consistent (HAC) variance estimator that accounts for both serial correlation and heteroskedasticity in the OLS residuals. Like robust SEs for cross-sectional data, they correct the uncertainty estimate but not the point estimates themselves — OLS is still used for \(\hat{\beta}\).
The "bandwidth" parameter determines how many lags of autocovariance are included in the estimator. A common rule of thumb: use \(\lfloor 4(n/100)^{2/9} \rfloor\) lags. Valid under weak dependence (not with unit roots).
Question 8
Lesson L03 · GLS / Quasi-Differencing
Under AR(1) errors \(u_t = \rho u_{t-1} + e_t\), the GLS transformation produces a model with uncorrelated errors. Describe the quasi-differenced model.
Type: Short Answer
Show Answer
For the model \(y_t = \beta_0 + \beta_1 x_t + u_t\) with \(u_t = \rho u_{t-1} + e_t\):
Step 1: Multiply the lagged equation by \(\rho\): \(\rho y_{t-1} = \rho\beta_0 + \rho\beta_1 x_{t-1} + \rho u_{t-1}\)
Step 2: Subtract from the original: $\(\underbrace{y_t - \rho y_{t-1}}_{\tilde{y}_t} = \beta_0(1-\rho) + \beta_1 \underbrace{(x_t - \rho x_{t-1})}_{\tilde{x}_t} + \underbrace{u_t - \rho u_{t-1}}_{e_t}\)$
The transformed model \(\tilde{y}_t = \beta_0(1-\rho) + \beta_1 \tilde{x}_t + e_t\) has i.i.d. errors \(e_t\) — OLS on this model is BLUE (GLS estimator).
Feasible GLS (FGLS): Since \(\rho\) is unknown, estimate \(\hat{\rho}\) from the OLS residuals: \(\hat{\rho} = \sum_{t=2}^T \hat{u}_t \hat{u}_{t-1} / \sum_{t=2}^T \hat{u}_{t-1}^2\). Substitute \(\hat{\rho}\) and apply the quasi-differencing transformation.
Question 9
Lesson L03 · Prais-Winsten vs Cochrane-Orcutt
Prais-Winsten estimation is preferred over Cochrane-Orcutt when:
Type: Multiple Choice
- A) The sample size is large
- B) Efficiency matters for small \(n\) — Prais-Winsten retains the first observation (in transformed form) while Cochrane-Orcutt discards it
- C) \(\rho\) is close to 1 (near unit root)
- D) There are multiple lags of serial correlation
Show Answer
Answer: B
Cochrane-Orcutt drops the first observation after quasi-differencing (the transformed \(\tilde{y}_1\) requires \(y_0\) which is unavailable). Prais-Winsten keeps it using the transformation: \(\tilde{y}_1 = \sqrt{1-\rho^2} \cdot y_1\), which is valid under stationarity.
For large \(n\), losing one observation is negligible. For small \(n\), Prais-Winsten is more efficient. When \(\rho\) is close to 1, both methods struggle — the transformation becomes near-differencing and loses information.
Question 10
Lesson L01 · Detecting Serial Correlation
A residual plot of \(\hat{u}_t\) against time shows long runs of positive residuals followed by long runs of negative residuals. This pattern suggests:
Type: Multiple Choice
- A) Heteroskedasticity
- B) Positive serial correlation — the sign of errors persists over time
- C) Omitted variable bias
- D) Negative serial correlation
Show Answer
Answer: B — Positive serial correlation
Long "runs" (many consecutive residuals of the same sign) are the visual signature of positive autocorrelation — each error tends to be followed by an error of the same sign. This is consistent with \(\hat{\rho} > 0\) and \(DW < 2\).
Negative serial correlation would appear as alternating positive/negative residuals (fast oscillation), corresponding to \(\hat{\rho} < 0\) and \(DW > 2\).
Heteroskedasticity appears as changing spread (fan pattern), not persistent runs of same-sign residuals.
Question 11
Lesson L03 · When to Use Each Remedy
Match each situation to the appropriate remedy for serial correlation.
Type: Short Answer
Show Answer
| Situation | Recommended remedy |
|---|---|
| Serial correlation present, want valid inference with minimal assumptions | Newey-West (HAC) standard errors — valid asymptotically; simple to implement |
| Serial correlation present, want efficient estimates (BLUE) | FGLS / Cochrane-Orcutt / Prais-Winsten — transforms the model for efficiency |
| Lagged dependent variable in model, suspecting serial correlation | Breusch-Godfrey test to detect; then Newey-West SEs (GLS won't work cleanly with LDV) |
| Serial correlation due to stochastic trend (unit root) | First-difference the series — removes the integrated component, leaving a stationary model |
| Serial correlation may be due to omitted lagged variables | Add FDL terms (\(x_{t-1}\), \(x_{t-2}\)) — correct the dynamic misspecification |
Question 12
Lesson L01 · Australian Context
[Short Answer] A researcher regresses Australia's quarterly inflation on the RBA cash rate and gets significant positive serial correlation (\(\hat{\rho} = 0.72\), \(DW = 0.56\)). What are two economic explanations for this serial correlation and what should the researcher do?
Type: Short Answer
Show Answer
Economic explanations:
-
Omitted slowly-changing variables: Supply-side factors (oil prices, productivity growth, global inflation) change gradually and affect Australian inflation persistently but are not included as regressors. Their effects show up as correlated errors.
-
Misspecified dynamics / adaptive expectations: Inflation expectations are formed adaptively from past inflation, creating persistence. The static model ignores that current inflation depends on past inflation (\(\pi_t = f(\pi_{t-1}, \ldots)\)), leaving this persistence in the error.
What to do:
- Short-run fix: Report Newey-West HAC standard errors to get valid inference without changing the model
- Better model: Add lagged inflation \(\pi_{t-1}\) as a regressor (or lagged cash rate) to absorb the dynamic effects — if the serial correlation disappears, the dynamic misspecification was the cause
- Test formally: Run Breusch-Godfrey with \(p = 4\) lags (quarterly data, seasonal consideration) before deciding on the remedy
- Check stationarity: If inflation has a unit root (unusual but possible in high-inflation periods), first-differencing may be needed